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1.An object is placed 95 cm from a concave mirror of radius 77 cm.
(a) Find the location of the image. (Enter in cm. Use a negative number if the image is behind the mirror)
_____cm
(b) What is the magnification of the mirror?
_____
Is the image real or virtual? Is the image upright or inverted? (Select all that apply.)
inverted
upright
virtual
real
2. A woman holds a tube of lipstick 9.2 cm from a spherical mirror and notices that the image of the tube is inverted and one third its normal size.
(a) Determine the position of the image. Is it in front of or behind the mirror? (Use a negative number below to indicate the image is behind the mirror.)
_____cm
(b) Calculate the focal length of the mirror.
_____cm
3. A dentist uses a mirror to examine a tooth that is 1.00 cm in front of the mirror. The image of the tooth is formed 15.0 cm behind the mirror.
(a) Determine the mirror's radius of curvature.
_____cm
(b) Determine the magnification of the image.
_____✕
4. A convex spherical mirror, whose focal length has a magnitude of 18.2 cm, is to form an image 10.8 cm behind the mirror.
(a) Where should the object be placed?
_____cm in front of the mirror
(b) What is the magnification of the mirror?
_____
5.To fit a contact lens to a patient's eye, a keratometer can be used to measure the curvature of the cornea-the front surface of the eye. This instrument places an illuminated object of known size at a known distance p from the cornea, which then reflects some light from the object, forming an image of it. The magnification M of the image is measured by using a small viewing telescope that allows a comparison of the image formed by the cornea with a second calibrated image projected into the field of view by a prism arrangement. Determine the radius of curvature of the cornea when p = 25.0 cm and M = 0.0160.
_____mm
6.A virtual image is formed 18.5 cm from a concave mirror having a radius of curvature of 39.0 cm.
(a) Find the position of the object.
_____cm in front of the mirror
(b) What is the magnification of the mirror?
_____
7. A concave makeup mirror is designed so that a person 30 cm in front of it sees an upright image magnified by a factor of two. What is the radius of curvature of the mirror?
R = _____ m
8. A concave mirror has a focal length of 34.3 cm.
(a) What is its radius of curvature?
_____cm
(b) Locate the image when the object distance is 100 cm. (Indicate the side of the mirror with the sign of your answer.)
_____cm
Describe the properties of the image when the object distance is 100 cm. (Select all that apply.)
real
virtual
upright
inverted
(c) Locate the image when the object distance is 10.0 cm. (Indicate the side of the mirror with the sign of your answer.)
_____cm
Describe the properties of the image when the object distance is 10.0 cm. (Select all that apply.)
real
virtual
upright
inverted
9. A man standing 1.54 m in front of a shaving mirror produces an inverted image 19.4 cm in front of it. How close to the mirror should he stand if he wants to form an upright image of his chin that is twice the chin's actual size?
_____cm
10. At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is 0.548 m.
(a) Locate the image of a patient 11.0 m from the mirror. (Use the correct sign conventions.)
_____cm (from the mirror)
(b) Indicate whether the image is upright or inverted.
upright
inverted
(c) Determine the magnification of the image.
_____
11. A cubical block of ice 51.0 cm on an edge is placed on a level floor over a speck of dust. Locate the image of the speck, when viewed from directly above, if the index of refraction of ice is 1.309.
_____cm below the upper surface of the ice
12. A contact lens is made of plastic with an index of refraction of 1.50. The lens has an outer radius of curvature of +2.05 cm and an inner radius of curvature of +2.43 cm. What is the focal length of the lens?
_____cm
13. A converging lens has a focal length of 34 cm. Locate the images for the following object distances if they exist. (Enter 0 in the q and M fields if no image exists.)
(a) 34.00 cm
q = _____
m = _____
Select all that apply to part (a).
real
upright
virtual
no image
inverted
(b) 11.33 cm
q = _____
m = _____
Select all that apply to part (b).
inverted
virtual
upright
no image
real
(c) 102.00 cm
q = _____
m = _____
Select all that apply to part (c).
inverted
virtual
upright
no image
real
14. A diverging lens has a focal length of magnitude 23.8 cm.
(a) Locate the images for each of the following object distances.
47.6 cm
distance _____cm
location in front of
23.8 cm
distance _____cm
location in front of
11.9 cm
distance _____cm
location in front of
(b)Is the image for the object at distance ___real or virtual?
real
virtual
(c) Is the image for the object at distance____ inverted or upright?
upright
inverted
(d)Find the magnification for the object
15. A converging lens is placed 40.0 cm to the right of a diverging lens of focal length 10.0 cm. A beam of parallel light enters the diverging lens from the left, and the beam is again parallel when it emerges from the converging lens. Calculate the focal length of the converging lens.
f = _____cm
16. Two converging lenses, each of focal length 14.9 cm, are placed 39.4 cm apart, and an object is placed 30.0 cm in front of the first lens. Where is the final image formed?
The image is located _____cm in front of the second lens.
What is the magnification of the system?
M = _____x
17. A 1.00-cm-high object is placed 3.05 cm to the left of a converging lens of focal length 7.05 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.
position_____cm in front of the second lens
height _____cm
Is the image inverted or upright?
upright
inverted
Is the image real or virtual?
real
virtual
1.An object is placed 95 cm from a concave mirror of radius 77 cm.
(a) Find the location of the image. (Enter in cm. Use a negative number if the image is behind the mirror)
_____cm
(b) What is the magnification of the mirror?
_____
Is the image real or virtual? Is the image upright or inverted? (Select all that apply.)
inverted
upright
virtual
real
2. A woman holds a tube of lipstick 9.2 cm from a spherical mirror and notices that the image of the tube is inverted and one third its normal size.
(a) Determine the position of the image. Is it in front of or behind the mirror? (Use a negative number below to indicate the image is behind the mirror.)
_____cm
(b) Calculate the focal length of the mirror.
_____cm
3. A dentist uses a mirror to examine a tooth that is 1.00 cm in front of the mirror. The image of the tooth is formed 15.0 cm behind the mirror.
(a) Determine the mirror's radius of curvature.
_____cm
(b) Determine the magnification of the image.
_____✕
4. A convex spherical mirror, whose focal length has a magnitude of 18.2 cm, is to form an image 10.8 cm behind the mirror.
(a) Where should the object be placed?
_____cm in front of the mirror
(b) What is the magnification of the mirror?
_____
5.To fit a contact lens to a patient's eye, a keratometer can be used to measure the curvature of the cornea-the front surface of the eye. This instrument places an illuminated object of known size at a known distance p from the cornea, which then reflects some light from the object, forming an image of it. The magnification M of the image is measured by using a small viewing telescope that allows a comparison of the image formed by the cornea with a second calibrated image projected into the field of view by a prism arrangement. Determine the radius of curvature of the cornea when p = 25.0 cm and M = 0.0160.
_____mm
6.A virtual image is formed 18.5 cm from a concave mirror having a radius of curvature of 39.0 cm.
(a) Find the position of the object.
_____cm in front of the mirror
(b) What is the magnification of the mirror?
_____
7. A concave makeup mirror is designed so that a person 30 cm in front of it sees an upright image magnified by a factor of two. What is the radius of curvature of the mirror?
R = _____ m
8. A concave mirror has a focal length of 34.3 cm.
(a) What is its radius of curvature?
_____cm
(b) Locate the image when the object distance is 100 cm. (Indicate the side of the mirror with the sign of your answer.)
_____cm
Describe the properties of the image when the object distance is 100 cm. (Select all that apply.)
real
virtual
upright
inverted
(c) Locate the image when the object distance is 10.0 cm. (Indicate the side of the mirror with the sign of your answer.)
_____cm
Describe the properties of the image when the object distance is 10.0 cm. (Select all that apply.)
real
virtual
upright
inverted
 |
| A Chart showing the sign conventions to describe the variables for a Mirror, Refracting Surface, and Thin Lens. |
9. A man standing 1.54 m in front of a shaving mirror produces an inverted image 19.4 cm in front of it. How close to the mirror should he stand if he wants to form an upright image of his chin that is twice the chin's actual size?
_____cm
10. At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is 0.548 m.
(a) Locate the image of a patient 11.0 m from the mirror. (Use the correct sign conventions.)
_____cm (from the mirror)
(b) Indicate whether the image is upright or inverted.
upright
inverted
(c) Determine the magnification of the image.
_____
11. A cubical block of ice 51.0 cm on an edge is placed on a level floor over a speck of dust. Locate the image of the speck, when viewed from directly above, if the index of refraction of ice is 1.309.
_____cm below the upper surface of the ice
12. A contact lens is made of plastic with an index of refraction of 1.50. The lens has an outer radius of curvature of +2.05 cm and an inner radius of curvature of +2.43 cm. What is the focal length of the lens?
_____cm
13. A converging lens has a focal length of 34 cm. Locate the images for the following object distances if they exist. (Enter 0 in the q and M fields if no image exists.)
(a) 34.00 cm
q = _____
m = _____
Select all that apply to part (a).
real
upright
virtual
no image
inverted
(b) 11.33 cm
q = _____
m = _____
Select all that apply to part (b).
inverted
virtual
upright
no image
real
(c) 102.00 cm
q = _____
m = _____
Select all that apply to part (c).
inverted
virtual
upright
no image
real
14. A diverging lens has a focal length of magnitude 23.8 cm.
(a) Locate the images for each of the following object distances.
47.6 cm
distance _____cm
location in front of
23.8 cm
distance _____cm
location in front of
11.9 cm
distance _____cm
location in front of
(b)Is the image for the object at distance ___real or virtual?
real
virtual
(c) Is the image for the object at distance____ inverted or upright?
upright
inverted
(d)Find the magnification for the object
15. A converging lens is placed 40.0 cm to the right of a diverging lens of focal length 10.0 cm. A beam of parallel light enters the diverging lens from the left, and the beam is again parallel when it emerges from the converging lens. Calculate the focal length of the converging lens.
f = _____cm
16. Two converging lenses, each of focal length 14.9 cm, are placed 39.4 cm apart, and an object is placed 30.0 cm in front of the first lens. Where is the final image formed?
The image is located _____cm in front of the second lens.
What is the magnification of the system?
M = _____x
17. A 1.00-cm-high object is placed 3.05 cm to the left of a converging lens of focal length 7.05 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.
position_____cm in front of the second lens
height _____cm
Is the image inverted or upright?
upright
inverted
Is the image real or virtual?
real
virtual
I'm struggling with chapter 23 hw, and I've already requested an extension. Do you know when you can post the videos?
ReplyDeleteThis evening, I have to write out my procedure for Org Lab, Do a molecular Cell outline, and hopefully start on the videos. I can't make any promises though and that looks like it might begin in the wee-hours of the morning.
DeleteI do apologize!
As a last resort, I have a typed solutions manual along with a calculator for each problem available for purchase. It's only $9.00 and I'm sure you'll understand how to work each problem after looking at what I have.
Hi Mike! Thanks for posting these videos, they are extremely helpful. I just watched the video for Ch. 23 #8 and you mentioned a chart to help determine when images are real vs. virtual and upright vs. inverted. I checked this blog page and can't seem to find the chart anywhere. Could you please repost it or attach a link to it? Thank you!
ReplyDeleteDone
DeleteAnonymous, I added the chart next to question number 8, above. I rewatched the video to remind myself of what you were talking about, and yep, sure enough, After I finished making those videos, I completely forgot to make the chart. But it's on here for you now!
ReplyDeleteThank you!
Delete